🏴‍☠️Merkle Hellman ( Cryptography )

We tired of RSA, try a new cryptosystem by merkle and hellman but we don't know how to decrypt the ciphertext. We need your help for decrypt the ciphertext to get back my flag.txt!

869B

merkle_hellman.tar.gz

merkle.py

b = [7352, 2356, 7579, 19235, 1944, 14029, 1084]
c = [8436, 22465, 30044, 22465, 51635, 10380, 11879, 50551, 35250, 51223, 14931, 25048, 7352, 50551, 37606, 39550]
r = ''
for x in range(len(c)):
    for i in range(128):
        mask = f"{i:07b}"
        t = 0
        for j, bit in enumerate(mask):
            if bit == "1":
                t += b[j]
        if t == c[x]:
            r += chr(i)
print(r)
#  ACSC{E4zY_P3@zy}